Find the positive difference between the solutions to the equation 6t^2 + 30 = 41t

re-write as

6t^2 - 41t + 30 = 0

Use Quadratic formula with a = 6     b=-41      c= 30 

\(x = {-(-41) \pm \sqrt{(-41)^2-4(6)(30)} \over 2(6)}\)

           to find    x = 6     and   x = 5/6           You can finish.....