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Find the quadratic function that has vertex (10, -7) and whose graph goes through the point (5, 168). 

f(x)=

 Jun 12, 2018
 #1
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Vertex form of a parabola is:
y=a(x-h)2+k; where (h,k) is the vertex

Vertex is given, plug them in.
y=a(x-10)2-7
 

Now we need to find the value of a.
Graph goes through (5,168), so plug those into x and y to solve for a.

168=a(5-10)2-7
175=a(-5)2

175=25a

a=7

 

With that, we now have the function of the parabola.
f(x)=7(x-10)2-7

 Jun 12, 2018

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