+81 Find the quadratic function that has vertex (10, -7) and whose graph goes through the point (5, 168).
f(x)=
+154 Vertex form of a parabola is:
y=a(x-h)2+k; where (h,k) is the vertex
Vertex is given, plug them in.
y=a(x-10)2-7
Now we need to find the value of a.
Graph goes through (5,168), so plug those into x and y to solve for a.
168=a(5-10)2-7
175=a(-5)2
175=25a
a=7
With that, we now have the function of the parabola.
f(x)=7(x-10)2-7
