Find the radius of a circle with an x-intercept of -2 if the circle’s center is (2,3) on a coordinate plane.
A.9
B.25
C.5
D.16
+9466 Remember, the radius of a circle is the distance between the center and a point on the circle.
The center of the circle is (2, 3)
The point (-2, 0) is on the circle.
Let's use the distance formula to find the radius.
radius = distance between (2, 3) and (-2, 0)
radius = \(\sqrt{(0-3)^2+(-2-2)^2}\)
radius = \(\sqrt{(-3)^2+(-4)^2}\)
radius = \(\sqrt{9+16}\)
radius = \(\sqrt{25}\)
radius = 5
Here's the graph: https://www.desmos.com/calculator/bewcrh6lwk
+9466 Remember, the radius of a circle is the distance between the center and a point on the circle.
The center of the circle is (2, 3)
The point (-2, 0) is on the circle.
Let's use the distance formula to find the radius.
radius = distance between (2, 3) and (-2, 0)
radius = \(\sqrt{(0-3)^2+(-2-2)^2}\)
radius = \(\sqrt{(-3)^2+(-4)^2}\)
radius = \(\sqrt{9+16}\)
radius = \(\sqrt{25}\)
radius = 5
Here's the graph: https://www.desmos.com/calculator/bewcrh6lwk
