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# I Need help plz

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Find the radius of a circle with an x-intercept of -2 if the circle’s center is (2,3) on a coordinate plane.

A.9

B.25

C.5

D.16

Jul 25, 2019
edited by Guest  Jul 25, 2019

#1
+5

Remember, the radius of a circle is the distance between the center and a point on the circle.

The center of the circle is  (2, 3)

The point  (-2, 0)  is on the circle. Let's use the distance formula to find the radius.

radius  =  distance between  (2, 3)  and  (-2, 0)

radius  =  $$\sqrt{(0-3)^2+(-2-2)^2}$$

radius  =  $$\sqrt{(-3)^2+(-4)^2}$$

radius  =  $$\sqrt{9+16}$$

radius  =  $$\sqrt{25}$$

Here's the graph: https://www.desmos.com/calculator/bewcrh6lwk

Jul 25, 2019

#1
+5

Remember, the radius of a circle is the distance between the center and a point on the circle.

The center of the circle is  (2, 3)

The point  (-2, 0)  is on the circle. Let's use the distance formula to find the radius.

radius  =  distance between  (2, 3)  and  (-2, 0)

radius  =  $$\sqrt{(0-3)^2+(-2-2)^2}$$

radius  =  $$\sqrt{(-3)^2+(-4)^2}$$

radius  =  $$\sqrt{9+16}$$

radius  =  $$\sqrt{25}$$