Find the real nth roots of x, if any. Give answers in simplest form
1. n=6 , x= -64
2. n=3 , x= 128
3. n=10 , x=1024
4. n=7 , x= -8sqrt2 / 2187
1.\(\sqrt[6]{64}=2\)
2.\(\sqrt[3]{128}=2^{\frac{7}{3}}\)
3.\(\sqrt[10]{1024}=2\)
4. Wow here comes the hardest question
\(\sqrt[7]{\frac{-8\sqrt2}{2187}}=\frac{((-2)^\frac{3}{7})(2^\frac{1}{14})}{3}=-\frac{\sqrt2}{3}\)
I think you've missed a minus sign in number 1 Max: x = -64
