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 Nov 9, 2019
edited by htzhang919  Nov 16, 2019
edited by htzhang919  Nov 16, 2019
 #1
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+2

(33818^2 + 33819^2 + 33820^2 + 33821^2 + 33822^2) mod 17 = 0

 

If you add up the remainders of each individual term mod 17 = 51

 

And 51 mod 17 = 0

 Nov 9, 2019
 #2
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thank you!!

 Nov 9, 2019
 #3
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Here’s a copy of the original question.

 

Find the remainder when \(33818^2 + 33819^2 + 33820^2 + 33821^2 + 33822^2\) is divided by 17

 

 

 

 

 

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GA

 Nov 16, 2019

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