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(33818^2 + 33819^2 + 33820^2 + 33821^2 + 33822^2) mod 17 = 0

If you add up the remainders of each individual term mod 17 = 51

And 51 mod 17 = 0

thank you!!

Here’s a copy of the original question.

Find the remainder when \(33818^2 + 33819^2 + 33820^2 + 33821^2 + 33822^2\) is divided by 17

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GA