Find the simplest polynomial with the given zeroes.
2i, -2i, 3
a. x^3-3x^2+4x-12
b. x^3+3x^2+4x-12
c. x^3-3x^2-4x+12
d. x^3+3x^2-4x-12
\((x-2i)(x+2i)(x-3)\\ =(x^2-4i^2)(x-3) \qquad | \qquad i^2 = -1\\ =(x^2+4)(x-3)\\ =x^3-3x^2+4x-12\)
(a)
(x-2i)(x+2i)(x-3) → (x^2 + 4)(x -3) → x^3 - 3x^2 + 4x - 12
