find the solution set of the equation 3x^2+36=0
3x^2 + 36 = 0 divide both sides by 3
x^2 +12 = 0
x^2 = -12
x = +- 2i sqrt3
3x^2+36=0 / Square root
3x + 6 = 0 / minus 6
3x = -6 / divide by 3
x= -2 YAY
Hello Guest..... Thanx for posting on the forum.
Did you try your answer in the equation to see if it 'works' ?
what do you think (3x+6)^2 equals? Might want to try it !