+0  
 
0
1541
1
avatar+523 

Find the sum of the series\(\sum_{n-1}^{15}(2n-1)\) . Show your work.

 

NOTE: The number (15) is suppose to be above (nominator), the Math symbol and (n-1) is suppose to be at the bottom (denominator).

 Feb 6, 2018
 #1
avatar
0

Is this what you mean?

∑[2n -1], n=-1 to 15 = 221

 Feb 6, 2018

3 Online Users

avatar