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Find the sum of the series\(\sum_{n-1}^{15}(2n-1)\) . Show your work.

 

NOTE: The number (15) is suppose to be above (nominator), the Math symbol and (n-1) is suppose to be at the bottom (denominator).

 Feb 6, 2018
 #1
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Is this what you mean?

∑[2n -1], n=-1 to 15 = 221

 Feb 6, 2018

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