Find the value of 533 using the identity (x + y)3 = x3 + 3x2y + 3xy2 + y3. Hint: 533 = (50 + 3)3; therefore, x = 50 and y = 3.
I dont get this at all?
i meant 53^3
(x + y)3 = x3 + 3x2y + 3xy2 + y3. (50 + 3)^3=x^3 + 3*x^2*y +3*x*y^2 + y^3
148,877 =50^3 +9*2,500 + 1,350 + 27
148,877=125,000 +22,500 + 1,350 + 27