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Find the value of 533 using the identity (x + y)3 = x3 + 3x2y + 3xy2 + y3.

Hint: 533 = (50 + 3)3; therefore, x = 50 and y = 3.

 

I dont get this at all?

 Feb 8, 2016
 #1
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i meant 53^3

 Feb 8, 2016
 #2
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 (x + y)3 = x3 + 3x2y + 3xy2 + y3.
(50 + 3)^3=x^3 + 3*x^2*y +3*x*y^2 + y^3

148,877 =50^3 +9*2,500  + 1,350 + 27

148,877=125,000 +22,500 + 1,350 + 27

 Feb 8, 2016

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