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Find the value of (h) when V = 52mm3, r = 6mm

 Jun 20, 2015

Best Answer 

 #1
avatar+14538 
+13

V=r2×π×h

        =>    h=V(r2×π)

 

h=52(62×π)h=0.4597809467099199

h=52[mm3](36[mm2]×π)
   = 0.46 mm

 

h = 0,46 mm

 Jun 20, 2015
 #1
avatar+14538 
+13
Best Answer

V=r2×π×h

        =>    h=V(r2×π)

 

h=52(62×π)h=0.4597809467099199

h=52[mm3](36[mm2]×π)
   = 0.46 mm

 

h = 0,46 mm

radix Jun 20, 2015
 #2
avatar+130462 
+5

Radix has assumed that this is a cylinder......it could also be a cone.....if so....the height (in cm) is .....

 

52=(13)×π×36×hh=13(3×π)h=1.3793428401297596

  

 

 

 Jun 20, 2015

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