Find the value of (h) when V = 52mm3, r = 6mm

$${\mathtt{V}} = {{\mathtt{r}}}^{{\mathtt{2}}}{\mathtt{\,\times\,}}{\mathtt{\pi}}{\mathtt{\,\times\,}}{\mathtt{h}}$$        =>    $${\mathtt{h}} = {\frac{{\mathtt{V}}}{\left({{\mathtt{r}}}^{{\mathtt{2}}}{\mathtt{\,\times\,}}{\mathtt{\pi}}\right)}}$$

$${\mathtt{h}} = {\frac{{\mathtt{52}}}{\left({{\mathtt{6}}}^{{\mathtt{2}}}{\mathtt{\,\times\,}}{\mathtt{\pi}}\right)}} \Rightarrow {\mathtt{h}} = {\mathtt{0.459\: \!780\: \!946\: \!709\: \!919\: \!9}}$$

$${\mathtt{h}} = {\frac{{\mathtt{52}}\left[{{mm}}^{{\mathtt{3}}}\right]}{\left({\mathtt{36}}\left[{{mm}}^{{\mathtt{2}}}\right]{\mathtt{\,\times\,}}{\mathtt{\pi}}\right)}}$$   = 0.46 mm

h = 0,46 mm

Radix has assumed that this is a cylinder......it could also be a cone.....if so....the height (in cm) is .....

$${\mathtt{52}} = \left({\frac{{\mathtt{1}}}{{\mathtt{3}}}}\right){\mathtt{\,\times\,}}{\mathtt{\pi}}{\mathtt{\,\times\,}}{\mathtt{36}}{\mathtt{\,\times\,}}{\mathtt{h}} \Rightarrow {\mathtt{h}} = {\frac{{\mathtt{13}}}{\left({\mathtt{3}}{\mathtt{\,\times\,}}{\mathtt{\pi}}\right)}} \Rightarrow {\mathtt{h}} = {\mathtt{1.379\: \!342\: \!840\: \!129\: \!759\: \!6}}$$