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$4x^{1/3}-2 \cdot \frac{x}{x^{2/3}}=7+\sqrt[3]{x}$

 Nov 5, 2020
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To start, note that $\frac{x}{x^{2/3}}=x^{1-\frac{2}{3}}=x^{1/3}$. Also note that we can rewrite the cube root with a fractional exponent, so $\sqrt[3]{x}=x^{1/3}$. Using these pieces of information, rewrite the given equation as:$$4x^{1/3}-2x^{1/3}=7+x^{1/3}$$Move all $x^{1/3}$ terms to one side and when simplified, you get x=343

 

yw

 Jul 3, 2021

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