Find the value of y so that the points (-2,5) and (8,y) lie on a line with slope -1/5
The slope=\(\frac{y_2-y_1}{x_2-x_1}=\frac{y-5}{8-(-2)}=\frac{y-5}{10}=\frac{-1}{5}\), so \(5y-25=-10, 5y=15, \boxed{y=3}.\)