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Find the value of y so that the points (-2,5) and (8,y) lie on a line with slope -1/5

 Dec 18, 2018

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 #1
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The slope=\(\frac{y_2-y_1}{x_2-x_1}=\frac{y-5}{8-(-2)}=\frac{y-5}{10}=\frac{-1}{5}\), so \(5y-25=-10, 5y=15, \boxed{y=3}.\)

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 Dec 18, 2018
 #1
avatar+3994 
+2
Best Answer

The slope=\(\frac{y_2-y_1}{x_2-x_1}=\frac{y-5}{8-(-2)}=\frac{y-5}{10}=\frac{-1}{5}\), so \(5y-25=-10, 5y=15, \boxed{y=3}.\)

tertre Dec 18, 2018

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