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Find the vertex of the graph of the equation $x - y^2 + 8y = 13$.

 Jul 15, 2022

Best Answer 

 #2
avatar+124676 
+2

Rearrange as

 

x =   y^2  - 8y   +  13                complete the square on y

 

x = y^2  - 8y  + 16  + 13  - 16

 

x = ( y - 4)^2  - 3

 

(x + 3)  = (y - 4)^2

 

The  vertex is   ( -3, 4)

 

Here's the graph  : https://www.desmos.com/calculator/tksqqrj5dc

 

cool cool cool

 Jul 15, 2022
 #1
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0

Completing the square, we get x = (y - 8)^2 - 51, so the vertex is (8,-51).

 Jul 15, 2022
 #2
avatar+124676 
+2
Best Answer

Rearrange as

 

x =   y^2  - 8y   +  13                complete the square on y

 

x = y^2  - 8y  + 16  + 13  - 16

 

x = ( y - 4)^2  - 3

 

(x + 3)  = (y - 4)^2

 

The  vertex is   ( -3, 4)

 

Here's the graph  : https://www.desmos.com/calculator/tksqqrj5dc

 

cool cool cool

CPhill Jul 15, 2022

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