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f (x)=x^2-5x-36

 May 13, 2014

Best Answer 

 #1
avatar
+5

You need to factor this function. Start with two sets of parenthesis, with x in both of them, for the x^2.

(x  )(x  ) To find what goes in these parenthesis, you must find two numbers that will add to give you -5 and mulitiply to give you -36.

-9 and 4:      -9+4=-5      -9*4=-36     Add these values to your parenthesis, keep the signs.

(x-9)(x+4)    Now set each set of parenthesis equal to 0 and solve.

x-9=0       x+4=0

x=9          x=-4

Your zeros are 9 and -4, which should be written in brackets.

 May 14, 2014
 #1
avatar
+5
Best Answer

You need to factor this function. Start with two sets of parenthesis, with x in both of them, for the x^2.

(x  )(x  ) To find what goes in these parenthesis, you must find two numbers that will add to give you -5 and mulitiply to give you -36.

-9 and 4:      -9+4=-5      -9*4=-36     Add these values to your parenthesis, keep the signs.

(x-9)(x+4)    Now set each set of parenthesis equal to 0 and solve.

x-9=0       x+4=0

x=9          x=-4

Your zeros are 9 and -4, which should be written in brackets.

Guest May 14, 2014
 #2
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This is an excellent answer.

Why don't you sign up and get credit for your great answers.  It is free and easy!

 May 14, 2014

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