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If f(x)=x^2-72 What are the zeros?

Duskrisen  Nov 28, 2018
 #1
avatar+14556 
+2

x^2 -72 = 0

x^2 = 72

x = +- sqrt (72)

ElectricPavlov  Nov 28, 2018
 #2
avatar+510 
+6

\(f(x) = x^2-72\). y = 0 when x^2 = 72. Square rooting both sides, we find that \(x = \pm\sqrt{72}\) or \(\boxed{x = \pm 6\sqrt{2}}\).

Hope this helps,

- PM 

PartialMathematician  Nov 28, 2018
 #3
avatar+510 
+4

graph:

 

https://www.desmos.com/calculator/knf4bbbesb

PartialMathematician  Nov 28, 2018

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