+0

# Find the Zeros

0
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If f(x)=x^2-72 What are the zeros?

Nov 28, 2018

#1
+18280
+2

x^2 -72 = 0

x^2 = 72

x = +- sqrt (72)

Nov 28, 2018
#2
+701
+1

$$f(x) = x^2-72$$. y = 0 when x^2 = 72. Square rooting both sides, we find that $$x = \pm\sqrt{72}$$ or $$\boxed{x = \pm 6\sqrt{2}}$$.

Hope this helps,

- PM

Nov 28, 2018
#3
+701
0

graph:

https://www.desmos.com/calculator/knf4bbbesb

Nov 28, 2018