+545 Find three consecutive odd integers such that the sum of the first and the third equals the sum of the second and 13.
how do you do this?
+5265 Odd intergers are 1,3,5,7,9,etc.,etc...
The equations are n+(2+n)+(4+n)=y and n+13=y
REMEMBER, odd numbers only.
So, let's try 5, 7, 9
5+7+9
12+9
21
Now, let's test out the second part of this problem.
13+7=21
20=21.
Wait a minute! 20 does NOT equal 21, so that doesn't seem right.
Try 3, 5, 7.
3+5+7=15
Test the second part of the equation.
5+13=15
18=15
Once again, incorrect. 18 does NOT equal 15.
try 7, 9, 11
7+9+11=27
Test the second part of the equation.
13+9=27
22=27
For the final time, INCORRECT. Therefore, there are no intergers that will work for that equation.
+1904 The three consecutive odd integers are \(11,13,15\). When you add the first and third numbers, \(11 & 15\), you get \(26\) and when you add the second number and 13 you get \(26\).
