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find two possible values of p if the lines px-y+1=0 and 3x+y+1=0 intersect at 45 degrees

 Jun 7, 2015
 #1
avatar+118696 
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I am rusty but I will give it a go.

find two possible values of p if the lines px-y+1=0 and 3x+y+1=0 intersect at 45 degrees

px-y+1=0             y=px+1             gradient =p

this line makes an angle of    atan(p)    with the positive axis    I'll call this  θ1

3x+y+1=0            y=-3x-1            gradient = -3

this line makes an angle of    atan(-3)    with the positive axis     I'll call this  θ2

 

Now we want

 θ1θ2=±π4

 

You need to use the last formula, do you think you can try to take it from here :)

 Jun 7, 2015
 #2
avatar+130458 
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I like how you did this one, Melody.......{I was "rusty" on this, as well}

 

 

 Jun 7, 2015
 #3
avatar+118696 
0

Thanks Chris

 Jun 7, 2015

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