Find value of K in which this equation is right:
(k -2) x^2 -5x +7=0
Only other information we have is the product of equation's roots = 7
So P=c/a = 7/1
\((k-2)x^2-5x+7=0\\ (k-2)x^2-5x=-7\\ (k-2)x^2=5x-7\\ k-2=(5x-7)/x^2\\ k=(5x-7)/x^2+2\)
+386 
