find x and y

Solve the following system:
{6 + 3 x - 2 y = 0 | (equation 1)
-6 + x + 2 y = 0 | (equation 2)
Express the system in standard form:
{3 x - 2 y = -6 | (equation 1)
x + 2 y = 6 | (equation 2)
Subtract 1/3 × (equation 1) from equation 2:
{3 x - 2 y = -6 | (equation 1)
0 x+(8 y)/3 = 8 | (equation 2)
Multiply equation 2 by 3/8:
{3 x - 2 y = -6 | (equation 1)
0 x+y = 3 | (equation 2)
Add 2 × (equation 2) to equation 1:
{3 x+0 y = 0 | (equation 1)
0 x+y = 3 | (equation 2)
Divide equation 1 by 3:
{x+0 y = 0 | (equation 1)
0 x+y = 3 | (equation 2)
Collect results:
Answer: |x = 0                 and                y = 3

From second equation : x = 6 - 2y   substitute this value of x into the first equation

3(6-2y) - 2y +6 = 0

18-6y-2y+6 = 0

24-8y=0

y=3                 SUstitute this value of y into one of the equations to find x     x +2(3) -6 = 0    then x= 0