+0

​Find x. Round to the nearest tenth if necessary.

0
317
7
+20

Find x. Round to the nearest tenth if necessary.

Select one:

a. 4

b. 5.5

c. 6

d. 5

Jul 30, 2018

#1
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Again, using power of a point, x^2+x=30. Solve from there.

Jul 30, 2018
#2
+20
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I have no clue what I'm doing, I have until AUG 2nd to pass this benchmark online. I'll cash app you if you help me plzz plzz

JLevy1203  Jul 30, 2018
#3
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Solving the quadratic, we get x=-6 or 5. x must be positive, so x=5

Guest Jul 30, 2018
#4
+20
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LOL I'm kind of talking about my benchmark.

JLevy1203  Jul 30, 2018
#5
0

Don't just try to get free answers, try to understand the concepts as well

Jul 30, 2018
#6
+20
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Not free,I'll cash app, I've got all the way to the end and now I'm stuck, the tutor I had was no help at all.

JLevy1203  Jul 30, 2018
#7
+21358
+1

​Find x. Round to the nearest tenth if necessary.

$$\begin{array}{|rcll|} \hline x\cdot (x+1) &=& 10 \cdot 3 \\ x^2+x &=& 30 \\ x^2+x-30 &=& 0 \\ (x-5)(x+6) &=& 0 \\\\ x_1 &=& 5 \\ x_2 &=& -6 \qquad \text{no solution, because }x \lt 0 \\ \hline \end{array}$$

d. 5

Jul 30, 2018