find X that 's contented to (2^X)x(3^X)=216

(2^x )* (3^x) = 216

(2.3)^x          = 216

6^x               = 216

6^x               =  6^3

x                   =  3//

2^x · 3^x  =  (2 · 3)^x  =  6^x  =  216   --->   x  =  3

or:  log(6^x)  =  log(216)

--->   x · log(6)  =  log(216)

--->   x  =  log(216) / log(6)  =  3

thanks