+15001 Find x, y, and z. (Leave answer in simplest radical form)
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\(y^2=36+x^2\)
\(\underline{z^2=10^2+x^2}\)
\(y^2-z^2=36-100\)
\(\underline{y^2+z^2=16^2}\)
\(2y^2=192\\ y^2=96\\ \color{blue}y=4\sqrt{6}=9.798\)
\(z^2=16^2-y^2\\ z^2=16^2-96\\ z^2=160\\ \color{blue}z=4\sqrt{10}=12.649\)
\(x^2=z^2-10^2\\ x^2=160-100\\ x^2=60\\ \color{blue}x=2\sqrt{15}=7,746\)
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