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Not sure if it's possible to find both acceleration AND time, but I appreciate any help on the following:

If you have a railgun with a 0.75-meter barrel which accelerates a 0.5 kg projectile to 2000 m/s and stops being accelerated by the railgun as it reaches the end of the barrel (0.75m), what is the length of time in seconds it accelerates and what is the magnitude of the acceleration in m/s^2?
 Jul 9, 2013
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If the rail gun works by causing a constant acceleration to a projectile that starts at velocity zero, then the equations for gravitational acceleration will work. The given distance equals gt(squared)/2 and the given speed equals gt, (Time t in seconds and acceleration g in m/sec(squared), and the given units for distance and speed.) So solve those two equations and you would have your answer for both g and t. (I got 7.5 ten-thousandths of a second for time, and 2.667 million meters per second-squared for the acceleration.) The reason this works can be found in any book on elementary (one-variable) integral calculus, or from a tutor.
 Jul 9, 2013

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