+279 
Okay The Drawing Is NOt to Scale.
Sorry If This Is Vague, I try My Best! Thank You For All Help!
the Problem is finding m<BAC in 0 the < sign Refers To the Angel!
+128599 Natasza...there is a theory in geometry that says when two sides of a triangle are equal, the angles opposite those sides are equal, too. Notice that in triangle AOB that OA = OB. So, that means that angle BAO = angle ABO.
Let's let the measure of each = x. So we have,
85 + x + x = 180
85 + 2x = 180 subtract 85 from both sides
2x = 95 divide by 2 on both sides
x = 47.5 And that's the measure of BAO. And BAO = BAC, so there's your answer.
+33616 Is O at the centre of the circle? If so, then OA = OB, so OAB is an isosceles triangle, and the other two angles are the same. If we call the other angles θ, then 2θ + 85 = 180, so 2θ = 95 and θ = 95/2 = 47.5°
+128599 Natasza...there is a theory in geometry that says when two sides of a triangle are equal, the angles opposite those sides are equal, too. Notice that in triangle AOB that OA = OB. So, that means that angle BAO = angle ABO.
Let's let the measure of each = x. So we have,
85 + x + x = 180
85 + 2x = 180 subtract 85 from both sides
2x = 95 divide by 2 on both sides
x = 47.5 And that's the measure of BAO. And BAO = BAC, so there's your answer.
