Triangle ABC is a right angled triangle,AB is perpendicular to BC,E is a point on BC,D is a point on AB ,intersection of AE and CD is F, AD=10,DB=8 BE=6,EC=10, Then find the area of quadrilateral DBEF.
See here :
Note that the area of triangle AEB =(1/2) AB * EB =(1/2) ( 18) (6) = 54 (1)
And the area of triangle ADF = (1/2) AD * height of 4 = (1/2) (10)(4) = 20 (2)
So [ DBEF ] = (1) - (2) = 54 - 20 = 34
