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Find the fourth term of (3x -2y^2)^5 ?

 Aug 1, 2014

Best Answer 

 #1
avatar+118723 
+5

the 4th term from which end.  I always find the wording of these question stupid! don't worry, it is not your fault 

(3x -2y^2)^5

 

$$5c3(3x)^3(-2y^2)^2 \\\\
=10(27x^3)(4y^4)\\\\
=1080x^3y^4\\\\
or\\\\
5C3(3x)^2(-2y^2)^3\\\\
=10*9x^2(-8y^6)\\\\
=-720x^2y^6\\\\$$

 

I expect someone will set me straight as to which answer is actually required! 

 Aug 1, 2014
 #1
avatar+118723 
+5
Best Answer

the 4th term from which end.  I always find the wording of these question stupid! don't worry, it is not your fault 

(3x -2y^2)^5

 

$$5c3(3x)^3(-2y^2)^2 \\\\
=10(27x^3)(4y^4)\\\\
=1080x^3y^4\\\\
or\\\\
5C3(3x)^2(-2y^2)^3\\\\
=10*9x^2(-8y^6)\\\\
=-720x^2y^6\\\\$$

 

I expect someone will set me straight as to which answer is actually required! 

Melody Aug 1, 2014
 #2
avatar
0

Thank you so much Melody. I'll just use both of your answers. Thank you for your patience :)

 Aug 1, 2014

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