256=2^n-1 how to solve for n? i need to do this for specialist by tonight :D
Edit: using Cas Calc i get n=9 yet i want to learn how to transpose the "n" to singulate it. plz help.
log (256) = log(2^(n-1))
log(256) = (n-1)log(2)
log (256)/log(2) = n-1
8=n-1
9=n