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avatar+2297 

Finding inverses (again)

 Aug 21, 2018
 #1
avatar+2297 
+2

Is #7 this: \(y=\frac{x^2-3}{2}\)

.
 Aug 21, 2018
 #2
avatar+94321 
+3

7.   

 y  = √[2x - 3]     square both sides

y^2  = 2x  - 3

y^2 + 3   = 2x     

[ y^2 + 3 ] / 2  =x

[x^2  + 3] / 2    = y

 

8. 

y = √[4x] - 7

y + 7  =√[4x]   square both sides

(y + 7)^2  = 4x

( y + 7)^2  / 4   = x

(x + 7)^2 / 4   = y

 

cool cool cool

 Aug 21, 2018

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