Finding missing sides/angels of triangles
cos=9/15
Since Cos=Adjacent/Hypotenuse, then here we have:
15^2=9^2 + O^2
O^2=225 - 81=144 take the sqrt of both sides
O=12, so the three sides are:15, 12, 9.
Cos(x)=.6
x=53.13 degrees one of the angles.
90 - 53.13=36.87 degrees-the 2nd angle
So, the three angles are: 90, 53.13, 36.87 degrees.