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cos=9/15

 Feb 5, 2016
 #1
avatar+8581 
+5

Cos=9/15

Cos=0.6

 Feb 5, 2016
 #2
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0

Which corresponds to an angle of 53.13 degrees

 Feb 5, 2016
 #3
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0

Finding missing sides/angels of triangles

cos=9/15

 

Since Cos=Adjacent/Hypotenuse, then here we have:

15^2=9^2 + O^2

O^2=225 - 81=144 take the sqrt of both sides

O=12, so the three sides are:15, 12, 9.

Cos(x)=.6

x=53.13 degrees one of the angles.

90 - 53.13=36.87 degrees-the 2nd angle

So, the three angles are: 90, 53.13, 36.87 degrees.

 Feb 5, 2016

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