Finding Simplest Form of Quotient

I will assume you mean

$\sqrt[3]{162}$ /$\sqrt[3]{2}$

cubrt(162) / cubrt(2)  =  cubrt(27 * 6)  /  cubrt (2) =  3 cubrt(6) / cubrt (2)  = 3 cubrt(2)cubrt(3) / cubrt(2) = 3 cubrt (3)

thank you!

ElectricPavlov is right. She/he is awesome. Sorry. I don't know if you are a girl or boy.

The way ElectricPavlov solved the problem is the short way.  Here is the long way.

$\frac{\sqrt[3]{162}}{\sqrt[3]{2}}$

$\frac{\sqrt[3]{27\times6}}{\sqrt[3]{2}}$

$\frac{\sqrt[3]{27}\sqrt[3]{6}}{\sqrt[3]{2}}$

$\frac{3\sqrt[3]{6}}{\sqrt[3]{2}}$

$\frac{3\sqrt[3]{6}\sqrt[3]{4}}{\sqrt[3]{2}\sqrt[3]{4}}$

$\frac{3\sqrt[3]{6\times4}}{\sqrt[3]{2\times4}}$

$\frac{3\sqrt[3]{24}}{\sqrt[3]{8}}$

$\frac{3\sqrt[3]{8\times3}}{\sqrt[3]{8}}$

$\frac{3\sqrt[3]{8}\sqrt[3]{3}}{\sqrt[3]{8}}$

$\frac{3\times2\sqrt[3]{3}}{\sqrt[3]{8}}$

$\frac{6\sqrt[3]{3}}{\sqrt[3]{8}}$

$\frac{6\sqrt[3]{3}}{2}$

$3\sqrt[3]{3}$