+0  
 
-1
159
1
avatar+16 

I do not know how to break down this problem in a simple way to find the answer.
\((1-i)^10\) (raised to tenth power, not \((1-i)^1 * 0\))

The choices are : -32i, -32 + 32i, 32, and 32 - 32i.
Thanks!

StayCurly  Dec 12, 2017
 #1
avatar+86931 
+3

( 1 - i )^10

 

[ (1 - i)^2 ] ^5

 

[ (1 - i) (1 - i ) ]^5

 

[ 1 - 2i + i^2 ]^5                {  i^2  =  -1 }

 

[  1 - 2i  - 1 ]^5  

 

[ - 2i ]^5

 

(-1)^5 * (2)^5  *  i^5                { i^5  =  i }

 

-1  *  32  *  i

 

-32 i 

 

 

 

cool cool cool

CPhill  Dec 12, 2017

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