\({k +3 \over 2(k -3)}\) in my textbook, they got \(-{5 \over 2}\) and 3 and i don't know how they got that?

Guest Mar 15, 2018

Remember that  we cant have any values that make a denominator  =  0

So.... k cannot   =3    because that makes the denominator 0


I don't know where they get  -5/2......this functiion is certainly defined at k  = -5/2


See the graph, here : https://www.desmos.com/calculator/hh4osmk1fc


I've substituted x for k, but the idea is still the same....



cool cool cool

CPhill  Mar 15, 2018

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