+564 a) Find the pH of a liquad if the concentration of hydrogen ions (H+) is 7.9 * 10^-9 mole per liter.
b) Find the concentration of hydrogen ions (H+) if the pH of the liquad is 3.2
+33616 pH is -log to base 10 of H+ concentration, so:
a. $${\mathtt{pH}} = {\mathtt{\,-\,}}{log}_{10}\left({\mathtt{7.9}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{-{\mathtt{9}}}\right) \Rightarrow {\mathtt{pH}} = {\mathtt{8.102\: \!372\: \!908\: \!709\: \!558}}$$
or pH≈8.1
b. $${\mathtt{conc}} = {{\mathtt{10}}}^{-{\mathtt{3.2}}} \Rightarrow {\mathtt{conc}} = {\mathtt{0.000\: \!630\: \!957\: \!344\: \!480\: \!2}}$$
conc of H+ ≈ 6.3*10-4
