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what are the zeros in 3x^2=12+4?

 Nov 10, 2015
 #1
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Solve for x:
3 x^2-16 = 0

Add 16 to both sides:
3 x^2 = 16

Divide both sides by 3:
x^2 = 16/3

Take the square root of both sides:
Answer: | 
| x = 4/sqrt(3)            or x = -4/sqrt(3)

 Nov 10, 2015

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