what are the zeros in 3x^2=12+4?
Solve for x: 3 x^2-16 = 0 Add 16 to both sides: 3 x^2 = 16 Divide both sides by 3: x^2 = 16/3 Take the square root of both sides: Answer: | | x = 4/sqrt(3) or x = -4/sqrt(3)