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If  is a constant such that 9x^2+24x^+a is the square of a binomial, then what is a?

 Sep 2, 2018
 #1
avatar+400 
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Let's turn a into s, to not get confused with another a. We can see that 9x2+24x+s=(ax)2+abx+abx+b2. This equals (a2)x2+(2ab)x+b2. We have that 9=(a2), 24=(2ab), and s=b2. By 9=(a2)a=3. If a=3, we can see that b=4. Then, we can get that s=16. So your answer would be a=16

 

- Daisy

 Sep 2, 2018
 #2
avatar+68 
+2

thanks!

 Sep 2, 2018
edited by isthebest123  Sep 2, 2018

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