If is a constant such that 9x^2+24x^+a is the square of a binomial, then what is a?
Let's turn a into s, to not get confused with another a. We can see that 9x2+24x+s=(ax)2+abx+abx+b2. This equals (a2)x2+(2ab)x+b2. We have that 9=(a2), 24=(2ab), and s=b2. By 9=(a2), a=3. If a=3, we can see that b=4. Then, we can get that s=16. So your answer would be a=16.
- Daisy