I think this is correct.....we have a binomial probability...

Probability that a die shows a 1 or 2 = 1/3

Probability that it shows something else = 2/3

We want to choose any two of the five die to show a 1 or a 2...so we have....

C (5,2) (1/3)^2 (2/3)^3 = 80 / 243 ≈ 32.9 %