in dry air the temperature decreases by about 0.65 degrees for each 100 meters so on a 10 degrees day what is the temperature at 2800 meters what would the formula be
Let the general formula for the temperature decrease be :
t(h) = (-0.65 / 100) h where t is the temperature decrease at some height, h ........so we have....
t(2800) = (-0.65/100)(2800) = -18.2 degrees
So........
10 - 18.2 = -8.2 degrees at 2800 ft
