For all real numbers x find the minimum value of

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For all real numbers x find the minimum value of \((x + 12)^2 + (x + 7)^2 + (x + 3)^2 + (x - 4)^2 + (x - 8)^2\)

Guest May 14, 2021

Guest · Answer 1 · 2021-05-14T12:53:13

Setting the derivative to 0, we get minimum value of 284.

ElectricPavlov · Answer 2 · 2021-05-14T01:20:16

Expanding and simplifying results in 5 x^2 + 20 x + 282 min occurs at x = - b/2a = -2

sub in that value for 'x' to calcualte the min value of the fxn = 262

For all real numbers x find the minimum value of ​