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For all x>4, log(x-4) + log(x) = ?

 Apr 7, 2015

Best Answer 

 #1
avatar+128707 
+5

As x approaches 4 from the rght side, this will approach negative infinity. To see why, when x = 4 + 10-n , the first term will be hugely negative as n gets larger and larger, and will "overpower" the second term which will only approach about .602 as n gets larger and larger.

As x assumes larger and larger values in the direction of infinity, the graph will appproach + infinity, because both terms grow without bound......but, it will do so very slowly......

Here's a graph......https://www.desmos.com/calculator/6jgfncj9kx

 

 

  

 Apr 7, 2015
 #1
avatar+128707 
+5
Best Answer

As x approaches 4 from the rght side, this will approach negative infinity. To see why, when x = 4 + 10-n , the first term will be hugely negative as n gets larger and larger, and will "overpower" the second term which will only approach about .602 as n gets larger and larger.

As x assumes larger and larger values in the direction of infinity, the graph will appproach + infinity, because both terms grow without bound......but, it will do so very slowly......

Here's a graph......https://www.desmos.com/calculator/6jgfncj9kx

 

 

  

CPhill Apr 7, 2015

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