For how many integer values of n between 1 and 120 inclusive does the decimal representation of n/120 terminate?

For how many integer values of n between 1 and 120 inclusive does the decimal representation of n/120 terminate?

The terminating decimal is if and only if the denominator has powers of only 2 and/or 5

The denominator is \(120 = 2^3\cdot {\color{red}3} \cdot 5^1\)

So \(n\) must drop the 3 in the denominator.

\(n = 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, \ldots , 117, 120\)

\(\begin{array}{|lrcll|} \hline AP: & a_n &=& 3+(m-1)*3 \quad & | \quad a_n = 120 \\ & 120 &=& 3+(m-1) * 3 \\ & 120 &=& 3+3m - 3 \\ & 120 &=& 3m \\ & m &=& \frac{120}{3} \\ & \mathbf{m} & \mathbf{=} & \mathbf{40} \\ \hline \end{array}\)

40 integer values of n between 1 and 120 inclusive does the decimal representation of \(\frac{n}{120}\) terminate.