For what real values of k does the quadratic 12x^2 + kx + 27 = 0 have nonreal roots? Enter your answer as an interval.

If a quadratic has nonreal roots, then the discriminant \(b^2-4ac<0\).

Plug in the values for b, a, and c into this equation to get \(k^2-4*12*27<0\). 

Rearrange to get \(k^2<4*12*27\). 

Now factorize 4*12*27 and solve to get \(-36 < k < 36\)

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