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For what values of x is the slope tangent to y=x^3+11x^2-x+17 equal to 0

Guest Mar 16, 2017

Best Answer 

 #2
avatar+79874 
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For what values of x is the slope tangent to y=x^3+11x^2-x+17 equal to 0

 

Take the derivative  and set to 0

 

3x^2 + 22x - 1   = 0

 

Solving this gives us

 

x ≈ 0.045176      and   x ≈  -7.3785

 

 

cool cool cool

CPhill  Mar 16, 2017
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1+0 Answers

 #2
avatar+79874 
+3
Best Answer

For what values of x is the slope tangent to y=x^3+11x^2-x+17 equal to 0

 

Take the derivative  and set to 0

 

3x^2 + 22x - 1   = 0

 

Solving this gives us

 

x ≈ 0.045176      and   x ≈  -7.3785

 

 

cool cool cool

CPhill  Mar 16, 2017

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