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avatar+65 

For x = (-2)^-3  solve this : A = (x - 2)*(x+5) - (x - 4)*(x + 3) + 4x

I just cannot find a way to solve this, so please if anyone actually helps can you  show how you solved it?

Thanks in advance

Lunar  Sep 23, 2015

Best Answer 

 #2
avatar+88898 
+10

For x = (-2)^-3  solve this : A = (x - 2)*(x+5) - (x - 4)*(x + 3) + 4x

 

x = (-2)^(-3)   = 1 / (-2)^3   = -1/8     so we have

 

A = [ (-1/8) - 2] [ (-1/8) + 5 ] - [ (-1/8) - 4 ] [(-1/8) + 3] + 4 [ -1/8 ]

 

A  = [ -17/8] [39/8] - [ -33/8][ 23/8] - 1/2 

 

A = [ -663 / 64] + [759/64] - 32/64 

 

A = [ 759 - 663 -  32 ] / 64 

 

A = 64 / 64  

 

A = 1

 

 

 

cool cool cool

CPhill  Sep 23, 2015
 #1
avatar
+5

The result of all those expressions=1

Guest Sep 23, 2015
 #2
avatar+88898 
+10
Best Answer

For x = (-2)^-3  solve this : A = (x - 2)*(x+5) - (x - 4)*(x + 3) + 4x

 

x = (-2)^(-3)   = 1 / (-2)^3   = -1/8     so we have

 

A = [ (-1/8) - 2] [ (-1/8) + 5 ] - [ (-1/8) - 4 ] [(-1/8) + 3] + 4 [ -1/8 ]

 

A  = [ -17/8] [39/8] - [ -33/8][ 23/8] - 1/2 

 

A = [ -663 / 64] + [759/64] - 32/64 

 

A = [ 759 - 663 -  32 ] / 64 

 

A = 64 / 64  

 

A = 1

 

 

 

cool cool cool

CPhill  Sep 23, 2015
 #3
avatar+65 
+1

Thanks alot!

Lunar  Sep 23, 2015
 #4
avatar+88898 
+5

No prob, Lunar.......

 

 

 

 

cool cool cool

CPhill  Sep 23, 2015

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