For x = (-2)^-3 solve this : A = (x - 2)*(x+5) - (x - 4)*(x + 3) + 4x
I just cannot find a way to solve this, so please if anyone actually helps can you show how you solved it?
Thanks in advance
For x = (-2)^-3 solve this : A = (x - 2)*(x+5) - (x - 4)*(x + 3) + 4x
x = (-2)^(-3) = 1 / (-2)^3 = -1/8 so we have
A = [ (-1/8) - 2] [ (-1/8) + 5 ] - [ (-1/8) - 4 ] [(-1/8) + 3] + 4 [ -1/8 ]
A = [ -17/8] [39/8] - [ -33/8][ 23/8] - 1/2
A = [ -663 / 64] + [759/64] - 32/64
A = [ 759 - 663 - 32 ] / 64
A = 64 / 64
A = 1
For x = (-2)^-3 solve this : A = (x - 2)*(x+5) - (x - 4)*(x + 3) + 4x
x = (-2)^(-3) = 1 / (-2)^3 = -1/8 so we have
A = [ (-1/8) - 2] [ (-1/8) + 5 ] - [ (-1/8) - 4 ] [(-1/8) + 3] + 4 [ -1/8 ]
A = [ -17/8] [39/8] - [ -33/8][ 23/8] - 1/2
A = [ -663 / 64] + [759/64] - 32/64
A = [ 759 - 663 - 32 ] / 64
A = 64 / 64
A = 1