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avatar+1314 
I'd like help with a few points and give some reasons how to solve as I couldn't solve or got close but calculations were wrong sign etc.



(2x^ 1/2 3x^1/3)^2 = 4x^5/3

(12a^ 1/2 / 4a^ 1/3)^2 = 9a^1/3 (i got 36x) a simplify website gave 36x (-10). Is the (-10) the amount reduced and not apart of the final answer?)

(6^-2)^-1 =36 (I got 6^1/3 and the simplify site gave 1/216)

27(2/3 - 2a)^3 - 8 (1-9a) =1-a (I solved to be 1a. Tried again and got the 1a.)

(2t^-1)^3 / 6t^2 = 4/3t^5 (i got 2t^3)

4t-6 3t^3 = fraction. How or why do we solve to be a fraction.



Please solve/simplify. I need to move on to other stuff.

As well, I found instances where solved answers are to positive indices and sometimes not though the answer is almost identical. What's the reason for deciding this?

Lastly, can you give rules to solve breaking the ^2 outside the bracket to inside for ( 5x^2 x^1/3 x x^-7)^2.
It seemed the sheet I am working of applies the power to ie. 5x^2 to both 5 and ^2, in other instances just the x^2 but not the 5. So I would like to confirm the rule.
 Feb 7, 2014
 #1
avatar+6198 
0
please rewrite all of this properly using parentheses. I can't figure out the expressions you actually mean.
 Feb 7, 2014
 #2
avatar+111156 
0
(2x^ 1/2 3x^1/3)^2 = 4x^5/3

Do you mean
[2x 1/2 * 3x 1/3] 2 = 4x 5/3

I wrote this with the help of the 'sup' button which is located above the smilies

to enter 3 2 just press
3 'sup'
the cursor will be put where you need to enter the index. Then move your curser to the end and keep going.

If you don't use the 'sup' button you need to add lots of brackets. Please use the sup button, it is so much easier for everyone to read
I'll do the first one - I may not interrprete your meaning properly.
[2x 1/2 * 3x 1/3] 2 = 4x 5/3

[2 2x 1 * 3 2x 2/3]= 4x 5/3

4x * 9x 2/3= 4x 5/3

36 x 5/3= 4x 5/3

x=0

I suspect that this was not the correct interpretation.
 Feb 7, 2014
 #3
avatar+1314 
0
Sure. I will use "sup" now. I didn't know what it was or see it. Thanks for pointing it out. Btw, some answers are wrong from the page I am working on, which I only just proved to be correct. Therefore I have left them out.

Here is the questions.
(2x 1/2 3x 1/3) 2 =

(12a 1/2 / 4a 1/3) 2 = (my answer =36x) a simplify website gave 36x( -10). What is the ( -10)?

(2t -1) 3 / 6t 2 = (i got 2t 3)

4t -6 3t 3 = fraction? How and why do we solve to a fraction?
 Feb 7, 2014
 #4
avatar+111156 
0
Stu:

Sure. I will use "sup" now. I didn't know what it was or see it. Thanks for pointing it out. Btw, some answers are wrong from the page I am working on, which I only just proved to be correct. Therefore I have left them out.

Here is the questions.
(2x1/2 3x1/3)2 =

(12a1/2 / 4a1/3)2 = (my answer =36x) a simplify website gave 36x(-10). What is the (-10)?

(2t-1)3 / 6t2 = (i got 2t3)

4t-6 3t3 = fraction? How and why do we solve to a fraction?


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Stu, if you are not doing so already, could you please read the nightly wrap post. It will help you understand what goes on here.
A number of times in the past I have requested that people give relevant titles to their posts, but it has limited effect.
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I think that these answers are all correct.
140207 Indices.JPG
 Feb 7, 2014
 #5
avatar+1314 
0
I don't understand the reduction at step 7 of *t n. Simply because it is only the sum of the top half of the fraction at 8, and if it were t n on the bottom would it apply the same principle? Am comfortable with the others now.
 Feb 7, 2014
 #6
avatar+111156 
0
Stu:

I don't understand the reduction at step 7 of *tn. Simply because it is only the sum of the top half of the fraction at 8, and if it were tn on the bottom would it apply the same principle? Am comfortable with the others now.



((2t -1) 3/6 * t 2

=[ 2 3(t -1) 3 *t 2] / 6

=8*t (-1*3) * t 2 /6

=8 * t -3+2 / 6

= 8 * t -1 / 6

= 8 / (6t)

= 4 / (3t)

I hope that helps Stu.
I've been watching your struggling with so many things at the same time. I think you need to settle down a bit and concentrate on one thing a time.
If you have mastered normal negative numbers then I suggest you concentrate on learning normal fraction manipulation next.
Go through a mathsisfun unit on fractions for a start.
I know that you need to learn a lot in a short period of time but I don't think that flitting between several topics at one time is going to work very well'
Just a suggestion.
 Feb 8, 2014
 #7
avatar+1314 
0
You are right, just working through the "expected to know stuff in strengthening foundations" and I'm going through maths is fun pages to. We'll have a day to discuss the sheet this week, not sure how many students have it to date. I want to be as up to speed as I can with this. As I do also need to move on to some statistics and trig. Thanks for the thought. And it's mostly self applied pressure atm to get ready and avoid a fast fall.
 Feb 8, 2014
 #8
avatar+111156 
0
Stu:

You are right, just working through the "expected to know stuff in strengthening foundations" and I'm going through maths is fun pages to. We'll have a day to discuss the sheet this week, not sure how many students have it to date. I want to be as up to speed as I can with this. As I do also need to move on to some statistics and trig. Thanks for the thought. And it's mostly self applied pressure atm to get ready and avoid a fast fall.



okay, good luck, we will help you as much as we can.
 Feb 8, 2014
 #9
avatar+1314 
0
yes thanks. I wasn't shown to move anything to the top in that fashion, as was done. Just shown to resolve, cancel and dismantle as is..actually I was, just in one step above and below. Great and thanks for the solve.
 Feb 8, 2014

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