\frac{\sqrt{2}+\sqrt{7}}{\sqrt{8}+\sqrt{7}}

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\frac{\sqrt{2}+\sqrt{7}}{\sqrt{8}+\sqrt{7}}

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\frac{\sqrt{2}+\sqrt{7}}{\sqrt{8}+\sqrt{7}}

Guest Apr 7, 2015

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$\frac{\sqrt{2}+\sqrt{7}}{\sqrt{8}+\sqrt{7}}\\\\ =\frac{(\sqrt{2}+\sqrt{7})(\sqrt{8}-\sqrt{7})}{(\sqrt{8}+\sqrt{7})(\sqrt{8}-\sqrt{7})}\\\\ =\frac{\sqrt{16}-\sqrt{14}+\sqrt{56}-7}{(8-7)}\\\\ =\frac{4-\sqrt{14}+\sqrt{4*14}-7}{(1)}\\\\ =4-\sqrt{14}+2\sqrt{14}-7\\\\ =-3+\sqrt{14}\\\\ =\sqrt{14}-3\\\\$

Melody Apr 8, 2015

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Melody · Answer 1 · 2015-04-08T10:14:06

$\frac{\sqrt{2}+\sqrt{7}}{\sqrt{8}+\sqrt{7}}\\\\ =\frac{(\sqrt{2}+\sqrt{7})(\sqrt{8}-\sqrt{7})}{(\sqrt{8}+\sqrt{7})(\sqrt{8}-\sqrt{7})}\\\\ =\frac{\sqrt{16}-\sqrt{14}+\sqrt{56}-7}{(8-7)}\\\\ =\frac{4-\sqrt{14}+\sqrt{4*14}-7}{(1)}\\\\ =4-\sqrt{14}+2\sqrt{14}-7\\\\ =-3+\sqrt{14}\\\\ =\sqrt{14}-3\\\\$

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\frac{\sqrt{2}+\sqrt{7}}{\sqrt{8}+\sqrt{7}}

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