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Cayden and Jayden had a total of $784. After Cayden spent 1/6 of his money on food and Jayden spent $124 on toys, they had the same amount left. How much money did Cayden have at first?

 Jun 22, 2021
 #1
avatar+318 
+4

Let's say cayden had x dollar. So Jayden had (784-x) dollar from 1st information.

From 2nd information:

x-x/6=(784-x)-124,

or, x*11/6=660

or, x=360.

So, cayden had 360$ at first.

 Jun 22, 2021
edited by Tgfromthe4  Jun 22, 2021
 #2
avatar+313 
+4

Let, Cayden had $x and Jayden had             $y.

According to the question,

                  x + y = 784          ...............(1)

and,         x - x6 = y - 124

                5x - 6y = -744        ................(2)

Solving equation (1) and (2)

eq(1) *6 + eq(2)

              6x + 6y = 4704

              5x - 6y = -744

         ...............................................

                   11x = 3960

                       x = 360

Therefore, Cayden had $360 at first.

 Jun 23, 2021
edited by apsiganocj  Jun 23, 2021
edited by apsiganocj  Jun 23, 2021
 #3
avatar+80 
+4

Let the amount clayden has be X

Given : 

sum of money clayden and jayden have=$784

So x+ amount jayden has =$784

Amount jayden has=$784-x

Clayden spent 16 =16* X

So amount left with clayden=x-x=x6

Amount left with clayden =5x6

Jayden spends $124 

So amount left with jayden = $784-$124-x

So amount left with jayden=$660-x

Given :both have same amount left 

Hence - 660-x=5x6

660*6-6x=5x

660*6=11x

60*6=x

360=x

Amount clayden has =$360

 Jun 26, 2021
 #4
avatar+58 
+4

c+j =784

left money 

5c6 = j- 124

5c6=784-c-124

11c6=660

c=360 (ans)

 Jun 26, 2021

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