Add the same number to both the numerator and the denominator ofthe fraction 7/17, to change it to 3/5.
\(\frac{7+x}{17+x} = \frac{3}{5}\)
\(5(7+x) = 3(17+x)\)
\(35 + 5x = 51 + 3x\)
\(2x = 16\)
\(\boxed{x=8}\)
.\(\frac{7+x}{17+x} = \frac{3}{5}\)
\(5(7+x) = 3(17+x)\)
\(35 + 5x = 51 + 3x\)
\(2x = 16\)
\(\boxed{x=8}\)