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Jonathan and Kenneth shared a sum of money in the ratio of 3 : 4. After Jonathan spent 1/6 of his money and Kenneth spent $15 of his money, both Jonathan and Kenneth had the same amount of money left. How much money did they have at first!

 Jul 9, 2021

Best Answer 

 #1
avatar+177 
+2

consider Sum of money shared by both =x

Total: 3+4=7

Jonathan shared money = 3*x/7

Kenneth shared money = 4*x/7

Given

3x/7 -1/6*(3x/7) = 4x/7-15

3x/7-x/14 = 4x/7-15

5x/14 = 4x/7 -15

5x/14-4x/7=-15

-3x/14=-15

3x=15*14

x=5*14

x=70 $

Jonathan shared money = 3/7*70=30$

Kenneth shared money = 4/7*70=40 $

 Jul 9, 2021
 #1
avatar+177 
+2
Best Answer

consider Sum of money shared by both =x

Total: 3+4=7

Jonathan shared money = 3*x/7

Kenneth shared money = 4*x/7

Given

3x/7 -1/6*(3x/7) = 4x/7-15

3x/7-x/14 = 4x/7-15

5x/14 = 4x/7 -15

5x/14-4x/7=-15

-3x/14=-15

3x=15*14

x=5*14

x=70 $

Jonathan shared money = 3/7*70=30$

Kenneth shared money = 4/7*70=40 $

apsiganocj Jul 9, 2021
 #2
avatar+1432 
+2

Jonathan and Kenneth shared a sum of money in the ratio of 3 : 4. After Jonathan spent 1/6 of his money and Kenneth spent $15 of his money, both Jonathan and Kenneth had the same amount of money left. How much money did they have at first!

 

J : K = 3x : 4x

 

J spent 3x/6

 

K spent $15

 

3x - (3x/6) = 4x - 15

 

x = 10

 

Jonathan had $30

 

Kenneth had $40

 Jul 9, 2021
edited by jugoslav  Jul 9, 2021

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