Ken and Ben shared some sweets. Ken took 2/7 of the sweets and Ben took the rest. If Ken took 18 fewer sweets than Ben, how many sweets did they have altogether at first?
From the problem, we have this information:
Kenn took 2/7 of the treats
and Ben took 5/7 of the treats
If Kenn took 18 fewer sweets than Ben, how many sweets did they have altogether at first?
First, we figure out how much more Benn took from the pile than Kenn.
We take Ben's total and subtract it from Kenn's total. Putting that in number form it looks like this:
5/7 - 2/7
Thankfully, it has the same denominator so we can subtract 5 from 2 which is 3.
Now we know that Ben has 18 (or 3/7) more treats than Kenn so we divide 18 and 3 to figure out 1/7 of the fraction which is 6
(because 6 multiplied by 3 is 18)
So now we know 1/7 is 6 we just have to multiply 6 by 7 to get our total. Multiplying it gets you 42
So in total, they had 42
Hope this helps! :D