Jason and Tina each had a set of flags. Tina had 4/9 as many flags as Jason. When Jason lost 21 flags, Tina then had twice as many as Jason. How many more flags did Tina have than Jason then?

Whayousayy May 12, 2021

#1**+1 **

T = 4J/9

2J - 42 = T

Solving, J = 27 and T = 12

27 - 21 is 6. and 12 - 6 = 6. The answer is 6.

HighSchoolDx May 12, 2021