Jason and Tina each had a set of flags. Tina had 4/9 as many flags as Jason. When Jason lost 21 flags, Tina then had twice as many as Jason. How many more flags did Tina have than Jason then?
T = 4J/9
2J - 42 = T
Solving, J = 27 and T = 12
27 - 21 is 6. and 12 - 6 = 6. The answer is 6.