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avatar+148 

Jason and Tina each had a set of flags. Tina had 4/9 as many flags as Jason. When Jason lost 21 flags, Tina then had twice as many as Jason. How many more flags did Tina have than Jason then?

 May 12, 2021
 #1
avatar+142 
+1

T = 4J/9

2J - 42 = T

 

Solving, J = 27 and T = 12

 

27 - 21 is 6. and 12 - 6 = 6. The answer is 6.

 May 12, 2021
 #2
avatar+93 
+1

i pretty sure the answer is 6 

 

 

if im wrong im sorry

 May 12, 2021

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